Given the net ion equationba2+ + so2−> baso4 ,how many grams of barium chloride must be present to react with 200grams of iron(iii)sulfate? (mwfe2(so4)3 = 400 g/mol, mwbacl2=208 g/mol)a. 564 g. b. 104 g. c. 34.7 g. d. 312 g. e. 1.5 g.

There must be present 312 g of barium chloride. (option d)

Explanation:

Ba⁺²   +   SO4⁻²   → BaSO4

BaCl2  →  Ba⁺²  +  2Cl⁻

Fe2(SO4)3 → 2Fe⁺³  +  3SO4⁻²

Molar mass Fe2(SO4)3 = 400 g/m

Mass / Molar mass = Moles

200g /400 g/m = 0.5 moles

If one mol of Iron(III) sulfate dissociates in 3 moles of sulfate,

how many moles of sulfate do i have, from 0.5 moles of Iron (III) sulfate.

1 mol Fe2(SO4)3 3 moles of SO4⁻²

0.5 mol Fe2(SO4)3 (0.5 . 3) /1 = 1.5 moles

Then 1 mole of sulfate anion will react with one mole of barium cation, which in turn comes from one mole of barium chloride, then 1.5 moles of sulfate anion, react with 1.5 moles of barium cation, which come from 1.5 moles of chloride. The ratio is always 1 to 1.

As we have the moles of barium chloride, let's find out the mass, with the molar weight.

Moles . molar weight = mass

1.5 moles . 208g/m = 312 g

why do the isotopes of a particular element behave differently in nuclear reactions but the same in chemical reactions? chemical reactions involve changes to electrons in an atom; isotopes do not differ in electrons, and so they react the same way during chemical changes.

they it depends on if one believes about radioactivity, they make a geiger counter beep but maybe it was going to beep anyway electronics do wierd things all the time or it was programmed to beep near certain metals.