You order a 16 oz glass of tea (where the mass of water is 474 grams) from a local restaurant. the tea is freshly brewed and has an initial temperature of 28.29 °c. you add ice to cool it. if the heat of fusion of ice is 6.020 kj/mol and each ice cube contains exactly 1 mol of water, how many ice cubes are necessary to cool the tea to 0.41 °c? the specific heat of the "tea" is 4.184 j/g*c.

Explanation:

It is known that relation between heat energy, specific heat and temperature change is as follows.

                  Q =

where,    q = heat energy

              m = mass

              C = specific heat

          = change in temperature = =

Therefore, calculate the heat energy as follows.

               Q =

                   =

                  = 55292.06 J

or,              = 55.3 kJ        (as 1 kJ = 1000 J)

One ice cube is equal to 1 mole.

Hence, 6.020 kJ/mol of energy absorbed by 1 ice cube. And, number of ice cubes absorbing 55.3 kJ of energy will be calculated as follows.

                 = 9

Thus, we can conclude that 9  ice cubes are necessary to cool the tea to .

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

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