What is the specific heat of an object that weighs 15 g in changes temperature from 30 degrees celsius to 37 degrees c when 50 joules of heat is added

c = 0.48 j/ g.  °C

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of object = 15 g

Change in temperature = 30 °C to 37°C

Heat absorbed = 50 J

Specific heat capacity = ?

Solution:

ΔT = 37 °C- 30 °C

ΔT = 7 °C

Now we will put the values in formula:

Q = m.c. ΔT

50 J = 15 g . c .  7 °C

c = 50 J / 105g. °C

c = 0.48 j/ g.  °C

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