When a solution of iron(iii) nitrate is mixed with a solution of sodium hydroxide, a rust colored precipitate forms. this precipitate is probably when a solution of iron(iii) nitrate is mixed with a solution of sodium hydroxide, a rust colored precipitate forms. this precipitate is probably a. iron (iii) nitrate. b. sodium hydroxide. c. iron (iii) hydroxide. d. sodium nitrate. e. none of the above

c. iron (III) hydroxide

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The balanced chemical equation for solution of iron(III) nitrate is mixed with a solution of sodium hydroxide is:

As iron(III) hydroxide is insoluble in water , it is formed as a solid which is called as precipitate.

When a solution of iron(III) nitrate is mixed with a solution of sodium hydroxide, the precipitate formed is iron (iii) hydroxide, Fe(OH)₃.

The correct answer to the question is Option C. Iron (III) hydroxide

To know which option is correct, we shall write the net ionic equation for the reaction between iron(III) nitrate and sodium hydroxide. This is given below:

iron(III) nitrate => Fe(NO₃)₃

Sodium hydroxide => NaOH

Fe(NO₃)₃(aq) + NaOH(aq) —>

Fe³⁺(aq) + NO₃¯(aq) + Na⁺(aq) + OH¯(aq) —> Fe(OH)₃(s) + Na⁺(aq) + NO₃¯(aq)

Thus, the correct answer to the question is Option C. iron (III) hydroxide

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the answer is 303.15 or 303