Chemistry, 18.11.2019 19:31, rhettperkins
What was the initial reactant concentration for the reaction described in part a? express your answer with the appropriate units. indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash. view available hint(s) hint 1. how to approach the problem opened hint use the integrated rate law for zero-order reactions [a]=−kt+[a]0 to solve for [a]0. values for [a] and t are given in part a, and your answer to part a was the value of k. you can use either data point given in part a to complete the calculation, however the corresponding time t and concentration [a] must be used together. [a]0 = previous answersrequest answer incorrect; try again use the integrated rate law for a zero-order reaction, and the values given in part a. you also calculated k in part a. keep in mind that the term is −kt, which will impact the addition and subtractions of terms as you solve for [a]0.
Answers: 2
Chemistry, 22.06.2019 14:20, montanolumpuy
7. in the cycle, a virus integrates its dna into the host's dna, and its dna is replicated when the host dna is replicated. a. infectious b. retroviral c. lysogenic d. lytic
Answers: 1
Chemistry, 23.06.2019 00:00, PineappleDevil889
2-bromo-2-methylbutane undergoes an e1 elimination reaction in the presence of ethanol. in the next reaction only one of the possible products is represented. although the product shown is not the major product of the reaction, notice that there is more than one way it can be produced. complete the mechanism and draw the missing substances.
Answers: 1
Chemistry, 23.06.2019 05:00, jjoyner
Question 5 match each term to its description. match term definition excess reactant a) reactant that can produce a lesser amount of the product limiting reactant b) reactant that can produce more of the product theoretical yield c) amount of product predicted to be produced by the given reactants
Answers: 2
What was the initial reactant concentration for the reaction described in part a? express your answ...
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