How many atoms are there in 10200ml of mustard gas (cl^2) at rtp?

3.84 × 10^24 atoms

We are given;

Volume of mustard gas = 10200 mL

We are required to calculate the number of atoms.

Note that one mole of  a gas occupies a volume of 24 L or 24000 mL at RTP.

Therefore, we can determine the number of moles of mustard gas;

Moles = Volume ÷ Molar gas volume (RTP)

          = 10200 mL ÷ 24000 mL/mol

          = 0.425 moles

But, 1 mole of a gas molecule contains a number of molecules equivalent to the Avogadro's number, 6.022 × 10^23.

Thus;

1 mole of Mustard gas = 6.022 × 10^23 molecules

Thus, we can determine the number of molecules of mustard gas;

Number of molecules = Moles × Avogadro's number

                                    = 0.425 moles × 6.022 × 10^23 molecules/mole

                                    = 2.56 × 10^23 molecules

We are required to determine the number of atoms.

Mustard gas has a chemical formula of C4H8Cl2S

Therefore, 1 molecule of mustard gas = 15 atoms

Thus, we can calculate the number of atoms;

Number of atoms = Molecules × Atoms/molecule

                             = 2.56 × 10^23 molecules × 15 atoms/molecule

                             = 3.84 × 10^24 atoms

Therefore, 10200 ml of mustard gas contains 3.84 × 10^24 atoms

he would use the colour black

the answer is c.the valence of the atoms combine .