What is the volume (in cm^ 3 ) of 1.2 moles of water vapor at rtp? calculate the mass of this water vapor.

Volume = 29400 cm³

Mass =  21.6 g

Explanation:

Given data:

Number of moles of water vapors = 1.2 mol

Mass of water vapor = ?

Volume of water vapors = ?

Solution:

Room temperature = 25 °C (25+273 = 298 K)

Room pressure = 1 atm

PV = nRT

V =  nRT/P

V = 1.2 mol × 0.0821 atm. K⁻¹. mol⁻¹ . L × 298 K/ 1 atm

V = 29.4 L

In cm³:

29.4 × 1000 = 29400 mL

mL = cm³

Mass of water vapors:

Mass = number of moles × molar mass

Mass = 1.2 mol × 18 g/mol

Mass =  21.6 g

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