If you dissolve 24.4 g of nacl in 251 g of water and generate a solution that has a density of 1.10 g/ml, what is the molarity of nacl in this solution? enter a numerical value in the correct number of significant figures. do not enter units in the answer box, but understand that the unit needed for the final answer is m.

The molarity of this NaCL solution is 1.83 M:

Explication:

Step 1: Data  given

Mass of NaCl = 24.4 grams

Mass of water = 251 grams

Density of water = 1.10 g/mL

Step 2: Calculate volume of water

Volume of water = Mass of water / density of water

Volume of water = 251 grams / 1.10 g/mL

Volume of water = 228.18 mL =0.22818L

Step 3: Calculate moles NaCl

Number of moles NaCl = 24.4 grams / 58.44 g/mol

Number of moles = 0.4175 moles

Step 4: Molarity of the solution

Molarity = Number of moles / Volume

Molarity = 0.4175 moles / 0.22818 L

Molarity = 1.83 M

The molarity of this NaCL solution is 1.83 M

linda: 3 ; laura: 15

step-by-step explanation:

note that linda + laura's age is 18, and that linda is 12 years younger than her sister.

let "linda" = x , "laura" = y:

x + y = 18

x = y - 12

first, plug in y - 12 for x in the first equation:

(y - 12) + y = 18

simplify.

2y - 12 = 18

isolate the variable (y). note the equal sign, what you do to one side, you do to the other. do the opposite of pemdas. first add, then divide.

2y - 12 (+12) = 18 (+12)

2y = 18 + 12

2y = 30

(2y)/2 = (30)/2

y = 30/2

y = 15

next, plug in 15 for y in the second equation (the other equation would work too).

x = y - 12

x = (15) - 12

x = 3

linda's age is 3, laura's age is 15.

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what are the choices?