Consider the balanced equation of k i ki reacting with p b ( n o 3 ) 2 pb(nox3)x2 to form a precipitate. 2 k i ( a q ) + p b ( n o 3 ) 2 ( a q ) ⟶ p b i 2 ( s ) + 2 k n o 3 ( a q ) 2ki(aq)+pb(nox3)x2(aq)⟶pbix2(s)+2kn ox3(aq) what mass of p b i 2 pbix2 can be formed by adding 0.528 l of a 0.417 m solution of k i ki to a solution of excess p b ( n o 3 ) 2 pb(nox3)x2?

50.7 g of precipitate is produced.

The equation of the reaction is; 2KI(aq) + Pb(NO3)2(aq) ⟶ PbI2(s) + 2KNO3 (aq)

We already know from the information in the question that the reactant in excess is Pb(NO3)2.

Number of moles of PbI2= 0.417 M × 0.528 L = 0.22 moles

From the stoichiometry of the reaction;

2 moles of KI yields 1 mole of PbI2

0.22 moles of KI yields  0.22 moles × 1 mole/2 moles

= 0.11 moles of PbI2

Mass of PbI2produced = number of moles of PbI2×  molar mass of PbI2

Molar mass of PbI2= 461 g/mol

Mass of PbI2produced = 0.11 moles of PbI2× 461 g/mol = 50.7 g of PbI2

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50.7 grams

Explanation:

To calculate the moles, we use the equation:

a) moles of

The balanced chemical equation is:

is the limiting reagent as it limits the formation of product and is in excess.

According to stoichiometry :

2 moles of give =  1 mole of

Thus 0.220 moles of give=  of

Mass of

Thus 50.7 g of will be formed.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.