How many moles of zncl, will be produced from 23.0 g of zn, assuming cucl, is available in excess?

23 g of Zn will produce 0.352 mole of zinc chloride.      

Explanation:

Given data:

mass of Zn = 23 g

Moles of ZnCl = ?

Solution:

Chemical equation:

2Zn + CuCl₂ → 2ZnCl + Cu

Number of moles of Zn:

Number of moles of Zn = mass/ molar mass

Number of moles of Zn = 23 g / 65.38 g/mol

Number of moles of Zn = 0.352 mol

now we will compare the moles of ZnCl with Zn because it is limiting reactant.

                         Zn       :      ZnCl  

                         2         :        2

                         0.352 :        0.352

So 23 g of Zn will produce 0.352 mole of zinc chloride.      

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i