3. what is the concentration of glucose (c6h1206, mm - 180.16 g/mol) solution that was prepared by
dissolving 50.500 g of glucose in 500.0 ml of solution? assume the solution has a density of 1.00
g/ml.

0.56 M

We are given;

Mass of glucose solute is 50.50 g

Volume of solution is 500 mL

We are required to calculate the concentration of glucose.

We need to know that, molarity is the concentration of a solution in moles per liter.

Molarity = Number of moles ÷ Molar mass

Molar mass of glucose = 180.16 g/mol

Mass of glucose = 50.50 g

Therefore, Moles of Glucose = 50.50 g ÷ 180.16 g/mol

                                                = 0.280 Moles

We can use the formula to calculate the molarity of glucose solution

Moles of glucose = 0.280 moles

Volume of solution = 500 mL or 0.5 L

Molarity = 0.280 moles ÷ 0.5 L

             = 0.56 moles/L

             = 0.56 M

Therefore, the concentration of glucose is 0.56 M

i'm wiling to try and you : )