The boiling point of chlorine (cl2) is 171.6 k. which of the following best predicts the boiling point of iodine (i2)?

a. lower than 171.6 k because permanent dipoles created in chlorine are stronger than temporary dipoles in iodine.

b. lower than 171.6 k because chlorine is more polar than iodine because of its higher electronegativity.

c. higher than 171.6 k because dispersion forces are stronger in iodine due to a greater number of electrons.

e. higher than 171.6 k because dipole-dipole interactions in iodine are stronger than dispersion forces in chlorine.

quartz

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answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole