86.14 ml of an acid solution was needed to neutralize 30.24 ml of a base solution of unknown concentrations. a second trial is run but this time 30.24 ml base solution is diluted to a total volume of 50.00 ml before starting the titration. how many ml of the acid solution are needed to neutralize it?
a) 45.26 ml
b) 86.14 ml
c) 61.11 ml
d) 52.10 ml

The correct answer is option B.

Explanation:

As given ,that 30.24 mL of base was neutralize by 86.14 mL of acid which means that moles of base present in 30.24 mL are neutralized by moles of acid present in 86.14 mL.

After dilution of base from 30.24 mL to 50.0 mL .Since, the moles of base are same in the solution as that of the moles in solution before dilution. Moles of acid require to neutralize the base after dilution will same as a that of present moles of acid present in 86.14 mL.

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