3. (2 points) suppose 53.0 ml of 0.320 m koh is mixed with 28.0 ml of 0.250 m hno3. what is the concentration of oh− ions after the reaction goes to completion? express your answer in mol/l.

The number of moles of excess hydroxide ions at the end of the reaction is 0.123 mol/L.

The equation of the reaction is;

KOH(aq) + HNO3(aq) >KNO3(aq) + H2O(l)

Number of moles of KOH = 53.0/1000 L ×  0.320 M = 0.01696 moles

Number of moles of HNO3 = 28/1000 L× 0.250 M = 0.007 moles

We can see that the acid, HNO3 is the limiting reactant so 0.007 moles of acid reacts with 0.007 moles base.

Number of moles of excess base = 0.00996 moles

Total volume of solution = 53.0 mL + 28.0 mL = 81 mL or 0.0081 L

Number of moles of excess base = 0.00996 moles/0.0081 L = 0.123 mol/L

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answer is: naturally occurring solid, inorganic compound or element is mineral.

minerals usually have crystalline form, that means than crystal constituents (atoms, molecules or ions) are arranged in a highly ordered microscopic structure, forming a crystal lattice that extends in all directions.

for example magnetite is a mineral of iron oxide (fe₂o₃).

calcite is a carbonate mineral and the most stable polymorph of calcium carbonate (caco₃).

dolomite is an   carbonate mineral composed of calcium magnesium carbonate (camg(co₃)₂).

the answer is 0.8m.

by: nicholas