If 12.2 g of lithium reacts with 12.2 g of oxygen what is the theoretical yield of the reaction in grams

45.57 g  of LiO

We are given;

Mass of Lithium = 12.2 g

Mass of oxygen = 12.2 g

We are required to calculate the theoretical yield of the reactant.

The reaction between Lithium and oxygen is given by;

2Li(s) + O₂(g) → 2LiO(s)

Moles of Lithium;

Moles = Mass ÷ Molar mass

Molar mass of Lithium = 6.941 g/mol

Therefore;

Moles of Lithium = 12.2 g ÷ 6.941 g/mol

                            = 1.758 moles

Moles of oxygen

Molar mass of oxygen = 16.0 g/mol

Moles of oxygen = 12.2 g ÷ 16.0 g/mol

                            = 0.7625 moles

From the reaction 2 mole of Li reacts with 1 mole of oxygen to produce 2 moles of LiO.

Therefore, Oxygen is the limiting reagent because it has fewer number of moles

1 mole of oxygen reacts to produce 2 moles of LiO.

Therefore, the mole ratio of oxygen to Lithium oxide is 1 : 2

Thus, moles of LiO = Moles of oxygen × 2

                               = 0.7625 moles × 2

                               = 1.525 moles of LiO

Mass = number of moles × Molar mass

Molar mass of LiO = 29.88 g/mol

Therefore;

Mass of LiO = 1.525 moles × 29.88 g/mol

                    = 45.567 g

                    = 45.57 g

Therefore, the theoretical mass of the product, LiO is 45.57 g

answer is: c. the experiment shows that the red substance experienced a chemical change.

this is chemical change (chemical reaction), because two new substances are formed (metalig liquid and gas), the atoms are rearranged and the reaction is followed by an energy change.

this is example of chemical decomposition.

chemical decomposition (analysis) is the separation of a single chemical compound into its two or more elemental parts or to simpler compounds.  

chemical decomposition is opposite of chemical synthesis.

i think it's c. if you look search electronic symbol on google and then click on wiki it shows you a