Many computer chips are manufactured from silicon, which occurs in nature as sio2. when sio2 is heated to melting, it reacts with solid carbon to form liquid silicon and carbon monoxide gas. in an industrial preparation of silicon, 155.4 kg of sio2 is allowed to react with 77.4 kg of carbon to produce 66.2 kg of silicon. a. what is the theoretical yield for the reaction in kg si?
b. what is the percent yield for the reaction?

Theoretical yield for Si = 2586.55*28.09= 72.7 Kg

Percentage yield is =2356.71/2586.55=91.11%

Explanation:

So the chemical equation for this reaction would be SiO2 + 2C = Si + CO

so n(SiO2)=m(SiO2)/M(SiO2)=155400/60.08=2586.55 mol

n(C)=m(C)/M(C)=77400/12.01=6444.63 mol

So Carbon is in exes.

n(Si)=m(Si)/M(Si)=66200/28.09= 2356.71 mol

Theoretical yield for Si = 2586.55*28.09= 72.7 Kg

Percentage yield is =2356.71/2586.55=91.11%

theoretical yield: 72.50kgSi

percent yield: 91.3%

Explanation:

The theoretical yield is limited by the initial mass of the limiting reactant, SiO2. The mass of  Si  can be calculated using stoichiometry as follows:

155.1 kgSiO2 ×1 kmol SiO2/ 60.085 kg SiO2 ×1 kmol Si/ 1kmol SiO2 ×28.085kg Si 1kmolSi= 72.50kg Si

Percent yield is a comparison of the theoretical yield to the actual yield. The mass of  Si  actually produced is given as 66.2  kg  . Dividing this by the theoretical yield (72.50  kg  ) and multiplying by 100 %  gives you the percent yield.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

the mantle

explanation:

earth is divided into three layers: the crust or the outermost layer on which we live; the underlying, middle layer - the mantle - and the core (the innermost layer of earth).