It has been determined that the body can generate 5500 kj of energy during one hour of strenuous exercise. perspiration is the body’s mechanism for eliminating this heat. what mass of water would have to be evaporated through perspiration to rid the body of the heat generated during 2 hours of exercise

There is 4.88 kg of water evaporated.

Explanation:

Step 1: Data given

5500 kJ of energy during one hour of strenuous exercise.

Δh = Heat of vaporization of water is 40.6 kJ/mol

Step 2: Calculate the mass of water evaporated

Q = 2* 5500 kJ = 11000 kJ

mass =  [( Q ) / ( Δh ) ] [ Molar mass of water]

mass  = [ ( 11,000 kj /  40.6  kJ/mol) * 18.02 g/mol )

mass = 4882.27 grams ≈ 4.88 kg of water

There is 4.88 kg of water evaporated.

there is none because earth is stationary and flat.

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.