Chemistry, 08.11.2019 06:31, exoticbunnylover123
7.23 th e condensation reaction of acetone, (ch3)2co (propanone), in aqueous solution is catalyzed by bases, b, which react reversibly with acetone to form the carbanion c3h5o−. th e carbanion then reacts with a molecule of acetone to give the product. a simplifi ed version of the mechanism is (1) ah + b → bh+ + a− (2) a− + bh+ → ah + b (3) a− + ha → product where ah stands for acetone and a− its carbanion. use the steadystate approximation to fi nd the concentration of the carbanion and derive the rate equation for the formation of the product.
Answers: 3
![\frac{d[product]}{dt}=K_{3}[A^{-}][HA]](/tpl/images/0365/1783/52b0c.png)
![\frac{d[A^{-}]}{dt}=K_{1}[AH][B] - K_{2}[A^{-}][BH^{+}]-K_{3}[A^{-}][HA]](/tpl/images/0365/1783/3cbda.png)
...(4)![\frac{d[B]}{dt}=-K_{1}[AH][B] +K_{2}[A^{-}][BH^{+}]=0](/tpl/images/0365/1783/4d945.png)
![[B]=\frac{K_{2}[A^{-}][BH^{+}]}{K_{1}[AH]}](/tpl/images/0365/1783/bbdf9.png)
....(5)![\frac{d[A^{-}]}{dt}=K_{1}[AH][\frac{K_{2}[A^{-}][BH^{+}]}{K_{1}[AH]} - K_{2}[A^{-}][BH^{+}]-K_{3}[A^{-}][HA]](/tpl/images/0365/1783/08b5f.png)
![\frac{d[A^{-}]}{dt}=-K_{3}[A^{-}][HA]](/tpl/images/0365/1783/bd67b.png)
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7.23 th e condensation reaction of acetone, (ch3)2co (propanone), in aqueous solution is catalyzed b...
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