0.0200 m fe3+ is initially mixed with 1.00 m oxalate ion, c2o42-, and they react according to the equation: fe3+(aq) + 3 c2o42-(aq) ⇄ [fe(c2o4)3]3-(aq) kc = 1.67 × 1020 what is the concentration of fe3+(aq) when equilibrium is reached? 1.67 × 1020 m 8.35 × 10-19 m 6.9a × 1021 m 1.44 × 10-22 m 0.980 am 0.940 m 0.0100 atm

Answer : The concentration of at equilibrium is 0 M.

Solution :  Given,

Concentration of = 0.0200 M

Concentration of = 1.00 M

The given equilibrium reaction is,

Initially conc.       0.02         1.00                   0

At eqm.             (0.02-x)    (1.00-3x)                x

The expression of will be,

By solving the term, we get:

Concentration of at equilibrium = 0.02 - x = 0.02 - 0.02 = 0 M

Therefore, the concentration of at equilibrium is 0 M.

output?

explanation:

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