Chemistry, 01.11.2019 01:31, chriscook6958

S–c has a bond order of 1, s=c and c=n have bond orders of 2, and c≡n has a bond order of 3. classify the bond orders of the equilibrium geometry structure of scn− by comparing its bond lengths to those found for ch3–s–ch3, s=ch2, h2c=nh, and hc≡n. the bond order for the s–c bond is and the bond order for the n–c bond is

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S–c has a bond order of 1, s=c and c=n have bond orders of 2, and c≡n has a bond order of 3. classif...