If you measured out 100.0g of water, how many molecules of water would you have drank?

3.342 x 10^24 molecules of water

Given;

Mass of water = 100.0 g

Required to determine the number of molecules in 100.0 g of water

Using Avogadro's constant

1 mole of a compound contains 6.022 × 10^22  molecules

Thus;

1 mole of H₂O contains 6.022 × 10^23 molecules

But;

1 mole = 18.02 g/mol

Therefore;

18.02 g of water contains 6.022 × 10^23 molecules

100.0 g of water will have;

= (100. 0 g ×6.022 × 10^23 molecules) ÷ 18.02

= 3.342 x 10^24 molecules

you didnt put any of the following

the term hydride is commonly named after binary compounds that hydrogen forms with other elements of the periodic table. hydride compounds in general form with almost any element, except a few noble gases. the trends and properties vary according to the type of intermolecular force that bonds the elements together, the temperature, its molecular masses, and other components. hydrides are classified into three major groups, depending on what elements the hydrogen bonds to. the three major groups are covalent, ionic, and metallic hydrides. formally, hydride is known as the negative ion of a hydrogen, h-, also called a hydride ion. because of this negative charge, hydrides have reducing, or basic properties. its special characteristics will be further discussed.

explanation: