One mole of carbon (12.0 g) in the form of crystalline graphite is burned at 25◦c and 1.000 atm pressure to form co2(g). all of the heat produced is used to heat a 5100 g bath of liquid water, originally at 25◦c. what is the final temperature of the water bath? the heat of formation of co2(g) is −393.5 kj/mol and the specific heat of water is 4.18 j/g/◦c. answer in units of ◦c

T₂ = 43.46 °C  

Explanation:

Given that:

The heat of the formation of carbon dioxide = - 393.5 kJ/mol (Negative sign suggests heat loss)

It means that energy released when 1 mole of carbon undergoes combustion = 393.5 kJ = 393500 J

Heat gain by water = Heat lost by the reaction

Thus,    

For water:  

Mass of water  = 5100 g

Specific heat of water = 4.18 J/g°C  

T₁ = 25 °C  

T₂ = ?

Q = 393500 J

So,

T₂ = 43.46 °C  

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.