Asample of water is heated from 10.0°c to 15.0°c by the addition of 125 j of heat. what is the
mass of the water?

5.97 g of water

Q = m × c × ΔT

In this case;

Quantity of heat, Q = 125 Joules

Change in temperature = 15°C - 10°C

                                       = 5°C

We know that the specific heat capacity of water is 4.186 J/g°C

Therefore, to get the mass we first rearrange the formula;

Mass = Q ÷ cΔT

        = 125 J ÷ (5°C × 4.186 J/g°C)

        = 5.97 g

Therefore, the mass of water is 5.97 g

The mass of a sample of water that is heated from 10.0°C to 15.0°C is 0.00595 kilograms.

Given the following data:

We know that the specific heat capacity of water is 4200 J/kg°C.

To find the  mass of the water:

Mathematically, quantity of heat is given by the formula;

Where:

Making mass the subject of formula, we have:

Substituting into the formula, we have:

Mass = 0.00595 kilograms

Therefore, the  mass of the water is 0.00595 kilograms.

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c most likely

hop this let me know if it is wrong