Convert 554 k/s into μk/ms in this problem all i need to know is what does the k is?

5,54x10⁵μK/ms

Explanation:

To solve this problem you don't need to know what the K is.

You need to know what mean SI prefixes. These prefixes are added at the beginning of an unit to make a new unit. For example a kilometer means 1000 meters, a miligram means 0,001 grams.

In this problem you have 554 K per s. 554K are:

554 K × = 5,54x10⁸ μK

1 s are:

1s × = 1000 ms

Thus 554 K/s are 5,54x10⁸ μK/ 1000 ms = 5,54x10⁵μK/ms

I hope it helps!

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years