What mass of calcium carbonate is produced from 5.11
mol of sodium carbonate?

There is 541.6 grams of calcium carbonate produced from 5.11 moles

Explanation:

Step 1: Data given

Number of moles of sodium carbonate ( Na2CO3) = 5.11 moles

Molar mass of sodium Carbonate:

⇒ Molar mass of Sodium = 22.99 g/mole

⇒ Molar mass of Carbon = 12.01 g/mole

⇒ Molar mass of Oxygen = 16 g/mole

Molar mass of Na2CO3 = 2* 22.99 + 12.01 + 3*16 = 105.99 g/mole

Step 2: Calculate mass of 5.11 moles of sodium carbonate

mass = number of moles of sodium carbonate * Molar mass of sodium carbonate

mass = 5.11 moles * 105.99 g/moles = 541.6 grams ≈ 542 grams

There is 541.6 grams of calcium carbonate produced from 5.11 moles Na2CO3

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

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