What mass of pcl5 will be produced from the given masses of both reactants? 28.0 g of p4 and 59.0 g of cl2

We have that from the Question, it can be said that  mass of PCl5 will be produced from the given masses of both reactants

From the Question we are told

What mass of will be produced from the given masses of both reactants? 28.0 g of P4 and 59.0 g of Cl2

Generally the equation for reaction is mathematically given as

Therefore

No of moles P_4=

No of moles P_4=0.225moles

No of moles of Cl_2=

No of moles of Cl_2=0.831 moles

0.831 mole of Cl_2=0.0.831 moles of P4 and produce 0.3324 moles PCl_5

Therefore

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PCl₅ mass = 69.3054 g

The reaction equation is the chemical formula of reactants and products

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reactants and products

Reaction

P₄ + 10 Cl₂ → 4 PCl₅

We look for moles of each reactant so we can determine the limiting of the reactants

mass 28.0 g

molar mass: 123.9

mole = mass : molar mass

mole = 28 : 123.9

mole: 0.2260

mass 59 g

molar mass: 71

mole = mass : molar mass

mole = 59 : 71

mole: 0.8310

From the coefficient of the equation above, it shows that the ratio of mol P₄: mol Cl₂ = 1:10

A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and small or exhausted reactans become a limiting reactants

ratio P₄: 0.2260: 1  = 0.2260

ratio Cl₂:  0.8310: 10 =  0.08310

Because Cl₂ ratio smaller then Cl₂ becomes the limiting  reactants

So mole PCl₅ is based on mole Cl₂

From the coefficient of reaction: mol PCl₅: mol Cl₂ = 4: 10

then mole PCl₅ = 4/10 x 0.8310 = 0.3324

molar mass PCl₅= 208.5

mass PCl₅ = mole x molar mass

PCl₅ mass = 0.3324 x 208.5

PCl₅ mass = 69.3054 g

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