30.0l of helium gas into moles of helium gas.

1.25 moles (R.T.P.) or 1.34 moles (S.T.P.)

Explanation:1 mole of a gas occupies a volume of 24 liters at room temperature and pressure (R.T.P.)On the other hand, 1 mole of a gas will occupy 22.4 Liters at standard temperature and pressure (S.T.P.)

Therefore, at R.T.P.

30.0 Liters will be equivalent to;

= 30.0 L ÷ 24 L

= 1.25 moles

At S.T.P

30.0 Liters will be equivalent to;

= 30.0 L ÷ 22.4 L

= 1.34 moles

Thus, 30.0 L of helium gas are equivalent to 1.25 moles of He at R.T.P. and 1.34 moles at S.T.P.

A. volume stays constant. just took took the quiz

21 just playing hshsjsjshsgdhdhdhhd