A3.2 liter sample of a gas is at 40 oc and 1.0 atmosphere of pressure. if the temperature decreases to 20 oc and the pressure decreases to 0.60 atmospheres, what is the new volume of the gas in liters?

V₂  = 5 L

Explanation

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 3.2 L

Initial pressure = 1 atm

Initial temperature = 40 °C (40 +273 = 313 K)

Final temperature = 20°C (20+273 = 293 K)

Final pressure = 0.60 atm

Final volume = ?

Solution:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 1 atm × 3.2 L × 293 K / 313 K × 0.60 atm

V₂  =  937.6 atm .L.  K  / 187.8 K . atm

V₂  = 5 L

the electrical  conductivity  of asolution  of an electrolyte is measured by determining the resistance of thesolution  between two flat or cylindrical electrodes separated by a fixed distance.

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