The specific heat capacity of thallium is 0.128 j/gc. a sample of thallium weighing 32.9 g is heated from 49c to its melting point(303 c). calculate the energy change involved.

Thallium absorbed 1069.645 J heat to reach to its melting point.

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of thallium = 32.9 g

specific heat capacity of thallium = 0.128 j/g. °C

Initial temperature = 49 °C

Final temperature = 303 °C

Solution:

Change in temperature = T₂- T₁

ΔT = 303 °C - 49 °C = 254 °C

Formula:

Q = m.c. ΔT

Q = 32.9 g ×0.128 j/g. °C × 254 °C

Q = 1069.645 J

Thallium absorbed 1069.645 J heat to reach to its melting point.

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i