Chemistry
Chemistry, 18.10.2019 18:30, hannahkharel2

When atoms lose more than one electron, the ionization energy to remove the second electron is always more than the ionization energy to remove the first. similarly, the ionization energy to remove the third electron is more than the second and so on. however, the increases in ionization energy upon the removal of subsequent electrons is not necessarily uniform. for example, consider the first three ionization energies of magnesium: first ionization energy 738kj/mol second ionization energy 1450kj/mol third ionization energy 7730kj/mol the second ionization energy is roughly twice the first ionization energy, but then the third ionization energy is over five times the second. use the electronic configuration of magnesium to explain why this is so? would you expect the same behavior in sodium? why or why not?

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When atoms lose more than one electron, the ionization energy to remove the second electron is alway...

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