35. ammonium perchlorate, nh co., is a common fuel component of solid fuel rockets. if 75% of the oxygen in nh. co. was converted to molecular oxygen, how many grams of molecular oxygen would be produced from 117.5 kg ammonium perchlorate? (atomic weights in amu: n = 14.01, ci = 35.45, 0 = 16.00, h = 1.008) a. 4.8 x 10^g 02 b. 6.4 x 10^g 02 c. 2.2 x 10^g 02 d. 2.4 x 10^g 02

The mass of molecular oxygen produced is

Explanation:

To calculate the number of moles, we use the equation:

     .....(1)

Given mass of ammonium perchlorate = 117.5 kg = 117500 g     (Conversion factor:  1 kg = 1000 g)  

Molar mass of ammonium perchlorate = 117.5 g/mol

Putting values in equation 1, we get:

The chemical equation for the decomposition of ammonium perchlorate follows:

By Stoichiometry of the reaction:

2 moles of ammonium perchlorate produces 3 moles of molecular oxygen

So, 1000 moles of ammonium perchlorate will produce = of molecular oxygen

Now, calculating the mass of molecular oxygen by using equation 1, we get:

Molar mass of molecular oxygen = 32 g/mol

Moles of molecular oxygen = 1500 moles

Putting values in equation 1, we get:

Hence, the mass of molecular oxygen produced is

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"