6. in the lewis structure of xef2, how many lone pairs are around the central atom? a. 3 b.4 c. 5 d. 6 e. 2

The correct answer is Option a.

Explanation:

To calculate the hybridization of central metal atom, we use the equation:

where,

V = number of valence electrons present in central atom  which is xenon = 8

N = number of monovalent atoms bonded to central atom  = 2

C = charge of cation  = 0

A = charge of anion  = 0

Putting values in above equation, we get:

The number of electron pair are 5 that means the hybridization will be and the electronic geometry of the molecule will be

But as there are 2 atoms around the central xenon atom, rest three positions will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent or linear.

Hence, the correct answer is Option a.

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms