Approximately how much plant available water would there be in 1 m of a clay loam soil with a soil water content of 23%? 30 mm 10 mm 50 mm 70 mm

30 mm

Explanation:

Given:

Permanent wilting point for the clay loam soil is approximately equals to 20% So,  

Thus,

Plant available water = 230-200 mm = 30mm

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1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%