Me! !

a balloon filled with some liquid is inflated and immersed underwater. the balloon remains at rest underwater. what would happen if the volume of the balloon decreased while the mass remained the same?

the balloon would remain at rest because the mass stays the same and so the forces on the balloon would not change.

the balloon would float and accelerate upwards because there would be a greater buoyant force acting on it than before.

the balloon would float and accelerate upwards because the smaller volume means it would take less force to make it float.

the balloon would sink and accelerate downwards because there would be a smaller buoyant force acting on it than before.

The balloon would sink and accelerate downwards because there would be a smaller buoyant force acting on it than before.

Explanation:

The density of a body is the ratio between its mass and its volume. A body float if its density is low and sink if its density is high.

As the ballon remain its mass but its volume decrease, the density will increase doing the ballon sink.

Thus, right answer is:

The balloon would sink and accelerate downwards because there would be a smaller buoyant force acting on it than before.

I hope it helps!

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

i think it is true since you can test the answer and can use observations to complete it.