Ametal sheet 7.5 mm thick with an area of 0.5 m2 has a temperature gradient applied across it, with the temperature on one side of the sheet fixed at 150 oc and the other at 50 oc. after a time, steady-state heat conduction is achieved. (a) plot and calculate the temperature gradient at steady state (b) add an arrow to your plot to indicate the direction of heat flow (c) calculate the heat loss through the sheet per hour if the sheet is made of aluminum (k=247 w/mk) and if the sheet is made of copper (k=398 w/mk). (d) imagine that the boundary conditions on the temperature are removed. what will eventually happen to the temperature gradient through the metal sheet? draw your answer on top of your plot from (a).

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

b. is the answer hoped i