Consider a reactant with an order of 1: what effect does that reactant have on the rate equation when the concentration is doubled 1) the reaction rate is double with respect to that reactant 2) the order doesnt effect the reaction so there will be no change 3) the reaction rate quadruples with respect to that reactant. 4) the reaction rate isn't changed by individual reactants so there will be no change.

1) The reaction rate is double with respect to that reactant

Explanation:

Hello,

By considering the rate law:

If we double the reactant A concentration, by definition, the rate will be doubled as well since the power is one (order 1), this could be proved just by checking it out in the rate law.

Best regards.

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noun

the practice of taking someone else's work or ideas and passing them off as one's own.

explanation:

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"