Chemistry, 15.10.2019 03:30, alisa1600000

1.how many ml of 0.401 m hi are needed to dissolve 5.97 g of baco3?
2hi(aq) + baco3(s) bai2(aq) + h2o(l) + co2(g)
2.calculate the number of milliliters of 0.757 m naoh required to precipitate all of the co2+ ions in 167 ml of 0.548 m coso4 solution as co(oh)2. the equation for the reaction is:
coso4(aq) + 2naoh(aq) co(oh)2(s) + na2so4(aq)

Answers: 1

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answered: abelsoto

The answer to your question is:

1.- volume = 0.151 l or 151 ml

2.- 0.241 l or 241 ml of NaOH

Explanation:

1.-

Data

V = ? HI = 0.401 M

BaCO3 = 5.97 g

2HI(aq) + BaCO3(s) ⇒ BaI2(aq) + H2O(l) + CO2(g)

MW BaCO3 = 137 + 12 + 48 = 197 g

197 g of BaCO3 1 mol

5.97 g x

x = (5.97 x 1) /197

x = 0.03 mol of BaCO3

2 moles of HI 1 mol of BaCO3

x 0.03 mol of BaCO3

x = (0.03 x 2) / 1

x = 0.060 mol of HI

Molarity = moles / volume

volume = moles / molarity

volume = 0.060 / 0.401

volume = 0.151 l or 151 ml

2.-

V = ? NaoH 0.757 M

Co⁺² Volume = 167 ml 0.548 M

CoSO4(aq) + 2NaOH(aq) ⇒ Co(OH)2(s) + Na2SO4(aq)

Moles of Co = Molarity x volume

Moles of Co = 0.548 x 0.167

Moles of Co = 0.092

1 mol of CoSO4 2 moles of NaOH

0.092 moles x

x = (0.092 x 2) /1

x = 0.183 moles of NaOH

Volume of NaOH = moles / molarity

= 0.183 / 0.757

= 0.241 l or 241 ml of NaOH

answered: Guest

he uptake of drugs from the intestine is often strongly influenced by diffusion. for example, consider a water-insoluble steroid for treating inflammation that is solubilized in aggregates of detergent molecules, called micelles. these micelles, aggregates of 80 soap molecules, have a molecular weight of 24,000, a diameter of 2.6 nm, and a charge of -27. the positively charge ions (counterions) in this system are na".

answered: Guest

i think that the answer is c

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1.how many ml of 0.401 m hi are needed to dissolve 5.97 g of baco3?
2hi(aq) + baco3(s) bai2(...