1.you wish to make a 0.325 m hydrochloric acid solution from a stock solution of 3.00 m hydrochloric acid. how much concentrated acid must you add to obtain a total volume of 50.0 ml of the dilute solution? in ml

2.in the laboratory you dilute 4.35 ml of a concentrated 12.0 m perchloric acid solution to a total volume of 50.0 ml. what is the concentration of the dilute solution? m

5.42 mL needed to be added and 1.04 M of dilute solution

Explanation:

For both cases, you need to use the expression:

M1*V1 = M2*V2

where M and V are concentration and volume.

For the 1st question, we have both concentrations, but we do not have both volume so:

3 * V1 = 0.325 * 50

V1 = 0.325 * 50 / 3

V1 = 5.42 mL need to be added.

For question 2:

Same as above, with the difference that we need to calculate concentration so:

12 * 4.35 = M2 * 50

M2 = 12 * 4.35 / 50

M2 = 1.04 M is the concentration of the diluted solution

b) nuclear ive learned that in a pedtrodic table