Chemistry, 11.10.2019 23:30, redthangracing
2.00 mol of h2(g) and 1.00 mol of i2(g) are placed in a 1.00 l container, and they react to form hi(g). at equilibrium, it is found that 1.80 moles of hi(g) are present in the container. calculate k for the reaction: h2(g) i2(g) ⇄ 2 hi(g)
Answers: 1
![k = \frac{[[HI]^{2} }{[H2][I2]}](/tpl/images/0311/6358/eab06.png)
![k = \frac{[1.8]^{2} }{[2][1]}](/tpl/images/0311/6358/ea4d9.png)
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2.00 mol of h2(g) and 1.00 mol of i2(g) are placed in a 1.00 l container, and they react to form hi(...
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