When the following equation is balanced, the coefficient of h3po4 is h3po4 (aq) + naoh (aq) → na3po4 (aq) + h2o (l)

The coefficient of H3PO4 is 1

Explanation:

The equation is H3PO4(aq) + NaOH (aq) → Na3PO4(aq) + H2O (l)

To balance the reaction, we first balance the Na atoms: On the right there are 3 Na atoms, so on the left we multiply NaOH by 3

The number of P atoms on the left is 1, the number of the P atoms on the right is also 1. So, this is already balanced.

On the left there are 6 H atoms, on the right we have 2H atoms, so e have to multiply H2O by 3.

On the left we have 7 O atoms, on the right, now we have also  7O atoms.

So this is already balanced.

The fully balanced reaction is H3PO4 (aq) + 3NaOH(aq) → Na3PO4(aq) + 3H2O(l)

The coefficient of H3PO4 is 1

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.