Raising 100 grams of water from 40 to 60 °c (the specific heat capacity of water is 1
cal
g
) requires the addition of

It requires the addition of 2000 calories

Explanation:

That is; Q = m×c×ΔT

In this case;

m = 100 grams

ΔT = 60°C-40°C

    = 20°C

Specific heat capacity,c,=1 cal/g

Thus;

Q = 100 g × 20°C × 1 cal/g

   = 2000 calories

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