What is the percentage composition of cf4

C = 13.64%

F = 86.36% 

Explanation:

Percentage composition = (mass/molar mass) x 100

Molar mass of CF4 = 88 

C = 12g/mol

F = 19g/mol

C = 12/88 x 100 = 13.64% 

F = 76/88 x 100 = 86.36%

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)

i think it's c. if you look search electronic symbol on google and then click on wiki it shows you a