The solubility of solid w in water is: 1.72 g/100 ml at 0°c, 21.3/100 ml at 100°c. a) how many ml of boiling water are required to dissolve 154.0 g of w? (report to the nearest ml) if solution were cooled to 0°c, how many grams of w would crystallize out? (report to one decimal place) b) what is the percent recovery? (report to one decimal place) (show calculations)

a) Mass of solid W crystallized out 0°C is 141.564 g

b) 91.92% is the percent recovery.

Explanation:

The solubility of solid W in water at 100°C = 21.3 g/100 mL

Volume of water at 100C required to dissolve 154.0 g of W: x

723.0 mL of water will dissolve 154.0 grams of solid W.

The solubility of solid W in water at 0°C = 1.72 g/100 mL

Mass of W soluble in 723.00 mL of water at  0°C = m

a) Mass of solid W crystallized out 0°C : 154.0 g- 12.436 g=141.564 g

b)  Percent recovery of solid at 0°C:

91.92% is the percent recovery.

ugh fiel iente of insistí is did kiwis jaj

the dissolution of polymer can be thermodynamically described in 2 steps.