Arigid tank contains 10 kg of water at 90°c. if 8 kg of the water is in the liquid form and rest is in vapor form determine: (a) pressure in the tank (b) volume of the tank

The pressure in the tank is 70.183 kPa and the volume of the tank is 4.73

Explanation:

Given that 8 kg of the water is in the liquid form and rest is in vapor we can say that the tank contains a saturated liquid-vapor mixture. Since the two phases coexist in equilibrium, the pressure must be the saturation pressure at the given temperature.

Use the Saturated water - Temperature table to find the pressure

From the Saturated water - Temperature table at 90 °C, we know that and .

To find the volume of the tank you can determine the volume occupied by each phase and then add them:

Volume of the liquid phase =

Volume of the vapor phase =

Volume of the tank = Volume of the liquid phase + Volume of the vapor phase

Volume of the tank =  + = 4.73

2b2t

explanation:

2b2t

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.