Arectangular tank is filled with water to a depth = h, the tank width and length are w and 1 respectively. calculate the ratio of the pressure force at the bottom to the pressure force on the side of the tank.

Explanation:

Given:

Depth = h

Width = w

Length  = 1

Now,

Let ρ be the density of water

Thus,

Pressure force at the bottom will be

= Pressure × Area

= ρgh × (w × 1)

also,

Pressure force at the sides will be = ρgh × (h × w)

Therefore,

The ratio of the pressure force at the bottom to the pressure force on the side of the tank will be

=

=

2b2t

explanation:

2b2t

sure im new too!

explanation: