The occupational safety and health administration has set the limit on the maximum percentage of carbon dioxide (co) in air a worker can breathe at 0.500% by mole. if dry ice (solid co2) is sublimating (becoming a gas) in a room at a rate of 0.500 mol/min, what is the minimum rate that fresh air has to be supplied to the room so that the concentration of co2 in the room doesn't exceed 0.500% by mole? assume the room is well mixed, and the volume of the solid dry ice does not change. number mol air/min what is the percent by mass of oxygen in a gaseous mixture whose molar composition is 0.500% co2 and 99.500% air? the composition of air is 21% mole o2, 79% mole n2, and has an average molar mass of 29.0 g/mol. number % o, by mass

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

i believe the answer is a.

b is the correct answer

mark me brainliest and hope this

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.