Aclosed tank is partially filled with seawater with density 1,030 kg/m3. if the pressure in the tank's airspace is 32 kpa and the depth of seawater is 9 m, what is the pressure at the bottom of the tank in pa and psi (lb/

The pressure at the bottom is 122 kPa or 17.7 psi.

Explanation:

The pressure at the bottom is equal to the pressure of the airspace plus the pressure of the seawater.

Pbottom = Pairspace + Pseawater    [1]

The pressure caused by the column of seawater can be calculated using the expression:

Pseawater = ρ . g . h    [2]

where,

ρ is the density of the seawater

g is the gravity (9.87 m/s²)

h is the depth of the seawater column

Solving [2]:

Pseawater = 1,030 kg/m³ x 9.87 m/s² x 9 m = 9 x 10⁴ kg/m.s² = 9 x 10⁴ Pa

Then, we use this result in [1]:

Pbottom = Pairspace + Pseawater

Pbottom = 32 kPa + 90 kPa = 122 kPa

We can express this result in psi, knowing that 1 psi = 6.89 kPa.

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.

the answer is 75.0%.