What is the wavelength in picometers for an electron with 360 ev of kinetic energy?

Wavelength = 64.635 pm

Explanation:

The expression for the deBroglie wavelength and kinetic energy is:

Where,  

is the deBroglie wavelength  

h is Plank's constant having value

m is the mass of electron having value

K.E. is the kinetic energy of the electron.

Given, K.E. = 360 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.6022 × 10⁻¹⁹ J

So, K.E. =

Applying in the equation as:

Also, 1 m = 10¹² pm

So, Wavelength = 64.635 pm

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