You have an-empty 42-gatbarrel-and-a 10-lb bag of dry alum, al2(so4). (a) calculate the number of gallons of 0.05 m solution you can make with this amount of alumthe-materials you hve on hand. (b) suppose you put all the alum into a 42-gal-the barrel and filled it full calculate the molar concentration of the resulting solution

a) 70.074 of gallons of 0.05 M solution we can make.

b) 0.0834 M is the molar concentration of the resulting solution.

Explanation:

Concentration of alum solution = c

Moles of alum  in solution = n

Volume of solution = V

a) Mass of alum = 10 lbs = 4535.92 g

(1 lb = 453.592 g )

Molar mass of alum

Moles of alum =

Volume of alum solution of 0.05 m = V

(1 L = 0.264172 gallons)

70.074 of gallons of 0.05 M solution we can make.

b) Moles of alum =

Volume of the barrel = 42 gallons  = 158.99 L

Concentration of alum : C

0.0834 M is the molar concentration of the resulting solution.

icc, international association for cereal chemistry

samuel de champlain. in 1608, king henry iv sponsored pierre dugua, sieur de mons and samuel de champlain as founders of the city of quebec with 28 men. this was the second permanent french settlement in the colony of canada.