Chemistry, 10.10.2019 00:00, Kassymatt

For the following reaction, kc = 15 at 700 k. 2 no(g) + cl2(g) ⇄ 2 nocl(g) if we have [no] = 0.15 m, [cl2] = 0.15 m, [nocl] = 0.40 m at 700 k, what will happen? group of answer choices the equilibrium will not shift. the equilibrium will shift to the left, but will use up only part of the nocl. the equilibrium will shift to the right, but will use up only part of the no and cl2. the equilibrium will shift to the right until all the reactants are used up. the equilibrium will shift to the left until all the nocl is used up.

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answered: Babybeast3544

Answer : The correct option is, The equilibrium will shift to the left until all the NOCl is used up.

Explanation :

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

$2NO(g)+Cl_2(g)\rightarrow 2NOCl(g)$

The expression for reaction quotient will be :

$Q=\frac{[NOCl]^2}{[NO]^2[Cl_2]}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(0.40)^2}{(0.15)^2(0.15)}=47.4$

The given equilibrium constant value is, K=15

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When that means product > reactant. So, the reaction is reactant favored.

When that means reactant > product. So, the reaction is product favored.

When Q=K that means product = reactant. So, the reaction is in equilibrium.

From the above we conclude that, the that means product > reactant. So, the reaction is reactant favored that means reaction must shift to the reactants to be in equilibrium or shift to the left side.

Hence, the correct option is, The equilibrium will shift to the left until all the NOCl is used up.

answered: Guest

For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

answered: Guest

the answer is minerals.